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That way you will know more about what you are up against, and it will help you when it comes time to formulate your action plans, which will be very different depending on whether you have five or five hundred instances to look after I know what you are asking yourself You are asking, Self, how do I find out what I am responsible for I suggest you start with your immediate supervisor and go from there The trail may take you to application managers and server administrators For example, your boss might say that you are responsible for the payroll databases But what are the payroll databases You may need to run with that initial bit of information and do some detective work to track down the specific databases involved Along your journey, you will be given an overview of the complexity that is your new home.

Complex(double real, double imag) : re(real), im(imag) { } // Allow a complex number to be created from a double. Complex(double real) : re(real), im(0.0) { } Complex(const Complex& c) { this->re = c.re; this->im = c.im; } // assignment operator Complex& operator=(const Complex& c) { this->re = c.re; this->im = c.im; return *this; } // equality operator for comparing two complex numbers bool operator==(const Complex& c) { return (this->re == c.re && this->im == c.im); } // unary minus Complex operator-() { return Complex(-re, im); } // Add a complex number to a complex number. Complex operator+(const Complex& rhs) { return Complex(this->re + rhs.re, this->im + rhs.im); } // Add a complex number to a complex number. Complex operator+(double d) { return Complex(this->re + d, this->im); } // Add a double and a complex number. // This must be a global friend operator. friend Complex operator+(double d, Complex c) { return Complex(c.re + d, c.im); }

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And when trying to maybe prove is too strong a word trying to justify to myself the correctness of some code I will often think in terms of an invariant and then prove that the invariant is maintained I think that s a fruitful way to think about it Seibel: How about stepping through code in a debugger Is that something you ll do if all else fails Steele: It depends on the length of the program And of course you can have tools that will help you to skip sections you don t need to step through because you re confident that those parts are OK And of course Common Lisp has this very nice STEP function, which is very helpful I ve stepped through a lot of Common Lisp code The ability to skip over particular subroutines whose details you trust, of course, buys you a lot.

Also the.

Guy Steele ability to set traps and say, I really don t need to look at this until this particular loop has gone around for the seventeenth time And there were hardware tools to support that on the PDP-10, which was nice, at least at MIT They tended to modify their machines in those days, to add features And there s a lot to be said for watching the actual execution of code in various ways Seibel: Do you ever try to formally prove your code correct Steele: Well, it depends on the code If I m writing code with some kind of tricky mathematical invariant I will go for a proof I wouldn t dream of writing a sorting routine without constructing some kind of invariant and proving it.

// ditto for ambition, distraction, uglification, and derision... }; Notice the operator + declared as a friend, which is a global function, not actually a member of the class. The friend operator is necessary if you want addition to be commutative (necessary for any sensible system of operators). Consider the following expressions: double d; Complex c1, c2; c2 = c1 + d; // Complex::operator+(double d) member function called c2 = d + c1; // global friend operator+(double d, const Complex& c) called It s not possible for an instance method to be called on a class when the class is on the right side of the expression. In C++/CLI, the operators that in classic C++ you would define as global friend functions, you define as static operators in the class. This is considered a superior design in that you do not need to make any special exceptions to the encapsulation of the private data for a class in order to support commutative operators that work with primitive types. In Listing 7-22, the addition operators between Complex and double are declared as static operators in the class. These operators would have been global friend functions in a native C++ class. In addition, the operator for adding two complex numbers could also be defined as static, as in Listing 7-22, rather than as a member operator as it would be in classic C++. Listing 7-22. Defining a Static Operator // complex.h using namespace System; value class Complex { double re; double im; public: Complex(double real, double imag) : re(real), im(imag) { } // unary minus Complex operator-() { return Complex(-re, im); }

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